\(\int \frac {(3-4 x+x^2)^2}{x^6} \, dx\) [2173]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 14, antiderivative size = 30 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=-\frac {9}{5 x^5}+\frac {6}{x^4}-\frac {22}{3 x^3}+\frac {4}{x^2}-\frac {1}{x} \]

[Out]

-9/5/x^5+6/x^4-22/3/x^3+4/x^2-1/x

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {712} \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=-\frac {9}{5 x^5}+\frac {6}{x^4}-\frac {22}{3 x^3}+\frac {4}{x^2}-\frac {1}{x} \]

[In]

Int[(3 - 4*x + x^2)^2/x^6,x]

[Out]

-9/(5*x^5) + 6/x^4 - 22/(3*x^3) + 4/x^2 - x^(-1)

Rule 712

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d +
 e*x)^m*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*
e + a*e^2, 0] && NeQ[2*c*d - b*e, 0] && IntegerQ[p] && (GtQ[p, 0] || (EqQ[a, 0] && IntegerQ[m]))

Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {9}{x^6}-\frac {24}{x^5}+\frac {22}{x^4}-\frac {8}{x^3}+\frac {1}{x^2}\right ) \, dx \\ & = -\frac {9}{5 x^5}+\frac {6}{x^4}-\frac {22}{3 x^3}+\frac {4}{x^2}-\frac {1}{x} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=-\frac {9}{5 x^5}+\frac {6}{x^4}-\frac {22}{3 x^3}+\frac {4}{x^2}-\frac {1}{x} \]

[In]

Integrate[(3 - 4*x + x^2)^2/x^6,x]

[Out]

-9/(5*x^5) + 6/x^4 - 22/(3*x^3) + 4/x^2 - x^(-1)

Maple [A] (verified)

Time = 16.55 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.83

method result size
norman \(\frac {-x^{4}+4 x^{3}-\frac {22}{3} x^{2}+6 x -\frac {9}{5}}{x^{5}}\) \(25\)
risch \(\frac {-x^{4}+4 x^{3}-\frac {22}{3} x^{2}+6 x -\frac {9}{5}}{x^{5}}\) \(25\)
gosper \(-\frac {15 x^{4}-60 x^{3}+110 x^{2}-90 x +27}{15 x^{5}}\) \(26\)
parallelrisch \(\frac {-15 x^{4}+60 x^{3}-110 x^{2}+90 x -27}{15 x^{5}}\) \(26\)
default \(-\frac {9}{5 x^{5}}+\frac {6}{x^{4}}-\frac {22}{3 x^{3}}+\frac {4}{x^{2}}-\frac {1}{x}\) \(27\)

[In]

int((x^2-4*x+3)^2/x^6,x,method=_RETURNVERBOSE)

[Out]

(-x^4+4*x^3-22/3*x^2+6*x-9/5)/x^5

Fricas [A] (verification not implemented)

none

Time = 0.34 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.83 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=-\frac {15 \, x^{4} - 60 \, x^{3} + 110 \, x^{2} - 90 \, x + 27}{15 \, x^{5}} \]

[In]

integrate((x^2-4*x+3)^2/x^6,x, algorithm="fricas")

[Out]

-1/15*(15*x^4 - 60*x^3 + 110*x^2 - 90*x + 27)/x^5

Sympy [A] (verification not implemented)

Time = 0.04 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=\frac {- 15 x^{4} + 60 x^{3} - 110 x^{2} + 90 x - 27}{15 x^{5}} \]

[In]

integrate((x**2-4*x+3)**2/x**6,x)

[Out]

(-15*x**4 + 60*x**3 - 110*x**2 + 90*x - 27)/(15*x**5)

Maxima [A] (verification not implemented)

none

Time = 0.19 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.83 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=-\frac {15 \, x^{4} - 60 \, x^{3} + 110 \, x^{2} - 90 \, x + 27}{15 \, x^{5}} \]

[In]

integrate((x^2-4*x+3)^2/x^6,x, algorithm="maxima")

[Out]

-1/15*(15*x^4 - 60*x^3 + 110*x^2 - 90*x + 27)/x^5

Giac [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.83 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=-\frac {15 \, x^{4} - 60 \, x^{3} + 110 \, x^{2} - 90 \, x + 27}{15 \, x^{5}} \]

[In]

integrate((x^2-4*x+3)^2/x^6,x, algorithm="giac")

[Out]

-1/15*(15*x^4 - 60*x^3 + 110*x^2 - 90*x + 27)/x^5

Mupad [B] (verification not implemented)

Time = 0.02 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.77 \[ \int \frac {\left (3-4 x+x^2\right )^2}{x^6} \, dx=-\frac {x^4-4\,x^3+\frac {22\,x^2}{3}-6\,x+\frac {9}{5}}{x^5} \]

[In]

int((x^2 - 4*x + 3)^2/x^6,x)

[Out]

-((22*x^2)/3 - 6*x - 4*x^3 + x^4 + 9/5)/x^5